A pinball machine uses a spring that is compressed 4.0 cm to launch a
ball. If the spring constant is 13 N/m, what is the force on the ball at the
moment the spring is released?

Respuesta :

Answer: 0.52N

Explanation:

Formula

F=ke

Givens

e= 4.0cm>>>0.04m

k=13N/m

Plug givens into formula

F= (13N/m)(0.04m)

F=0.52N

The force on the ball at the moment the spring is released will be F =0.52N

What is a  spring force  ?

When a spring is stretched or compressed , it displaces from equilibrium position . As a result , a restoring force will act ( which act opposite to the direction of force applied on the string ) and tends to retract the spring back to its original position . The force is called spring force

Given

x = 4cm  = 0.04 m

spring constant is(k) =  13 N/m

F( spring force on the ball ) = ?

F = -k x

F  = -(13)(.04)

F ( spring force) = - 0.52N

The force on the ball at the moment the spring is released will be F =0.52N

learn more about spring force

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