Which of the following equations has a graph in the
xy-plane for which y is always greater than or equal
to -1 ?
A) y = |x| - 2
B) y = x2 - 2
C) y = (x - 2)2
D) y = x3 - 2

Respuesta :

Answer: (x-2)2

Step-by-step explanation:

The required equation is  [tex]y=(x-2)^2[/tex]

The correct answer is an option (C)

What is an equation?

"It is a mathematical statement which consists of equal symbol between two algebraic expressions."

For given question,

We have been given four equations.

We need to find an equation for which y is always greater than or equal

to -1.

Consider,

A. y = ∣x∣ - 2

We know that the minimum value of ∣x∣ is 0.

So, the minimum value of y becomes -2

Hence, this is not a required equation.

B. [tex]y=x^{2} -2[/tex]

We know that the square of any number is always positive.

The minimum value of [tex]x^{2}[/tex] is 0.

So, the minimum value of y becomes −2

Hence, this is not a required equation.

C. [tex]y=(x-2)^2[/tex]

We know that the square of any number is always positive.

The minimum value of y is zero.

This means, the y value of equation  [tex]y=(x-2)^2[/tex] is always greater than -1.

D. [tex]y=x^3-2[/tex]

We know that [tex]x^3[/tex] can go have negative values. This means it may have value that tends to negative infinity.

This means, the y can be less than -1 and this is not a required equation.

Therefore, the required equation is  [tex]y=(x-2)^2[/tex]

The correct answer is an option (C)

Learn more about the equation here:

https://brainly.com/question/13170101

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