23-03-2021
Physics

contestada

An object, accelerating from rest at a constant rate, travels over 28 m in 11 s. What is its final velocity?

1.81 m/s

3.20 m/s

5.09 m/s

0.00 m/s

none of the above

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menushaeshan menushaeshan

23-03-2021

Answer:

answer is 3

Explanation:

by using s= [(v+ u)/2] x t

28= (v+ 0)/2 x 11

v= 5.09 ms^-1

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