Answer:
0.219 mol HCI
Explanation:
Iron(II) sulfide reacts with hydrochloric acid according to the reaction:
FeS (s) + 2HCl (aq) → FeCl2 (s) + H2S (g)
A reaction mixture initially contains 0.223 mol FeS and 0.665 mol HCl.
Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains?
