Answer:
The new volume is approximately 17.637 liters
Explanation:
The given parameters in the question are;
The initial volume of the gas, V₁ = 13.5 Liter
The initial temperature of the gas, T₁ = 248 K
The new temperature of the gas, T₂ = 324 K
A balloon containing gas that experiences an increase in the temperature of the gas content under constant pressure obeys Charles law which states that the volume of a given mass of gas is directly proportional to its Kelvin temperature is expressed mathematically as follows;
[tex]\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}[/tex]
Where;
V₁ = The initial volume of the gas
T₁ = The initial temperature of the gas
V₂ = The new volume of the gas
T₂ = The new temperature of the gas
From the question, we have;
V₁ = 13.5 Liter
T₁ = 248 K
T₂ = 324 K
Therefore, we have;
[tex]{V_2}= \dfrac{V_1}{T_1} \times T_2[/tex]
[tex]{V_2}= \dfrac{324 \ K}{248 \ K} \times 13.5 \ L=17\dfrac{79}{124} \ L\approx 17.637 \ L[/tex]
The new volume, V₂ ≈ 17.637 L.
