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A cylindrical candle has a diameter of 2 inches and a height of 6 inches, as shown below.

Which is closest to the total surface area of the candle?

F) 75 in.2

G) 38 in.2

H) 44 in.2

J) 100 in.2

A cylindrical candle has a diameter of 2 inches and a height of 6 inches as shown below Which is closest to the total surface area of the candle F 75 in2 G 38 i class=

Respuesta :

randiwan

Answer:

44 in^2

Step-by-step explanation:

The surface area is 2 circles and one rectangular shape side, the area for the circle is A = pi*r^2 = 1^2*pi, and side area is circumference of the circle times height, so A side = pi*D*height = 2pi*6 =12pi.

So total surface area = 2pi + 12pi = 14pi =43.98 = 44 in^2

If it is helpful, plz give me Brainliest.

The closest to the total surface area of the cylinder is 44 inches²

Total surface area of a cylinder:

  • a = 2πr(r+h)

where

r = radius

h = height

Therefore,

r = 2 / 2 = 1 inch

h = 6 inches

a = 2 × 3.14 × 1(1 + 6)

a = 6.28(7)

a = 43.96

a ≈ 44 inches²

learn more on cylinder here: https://brainly.com/question/88892

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