Answer:
First we can find the area of thesemicircle below
[tex]s = \frac{1}{2} \pi {r}^{2} = \frac{1}{2 } \times 3.14 \times 100 = 157[/tex]
Secend we can find the area of triangle that is equal to
[tex]t = \frac{1}{2} \times 12 \times 16 = 96[/tex]
Then we can find the blow area that is equal to
[tex]s - t = 157 - 96 = 61[/tex]
That is what do you want
Step-by-step explanation:
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