Answer:
Step-by-step explanation:
First you need to calculate the entire length (in meters) of the metal used in the gate, then multiple the length by 2.5 kg per meter
Break it into parts.......
four pieces on along the outside is just the perimeter of a rectangle
P = 2( L + H) both sides and the top and bottom
the two crossing metal pieces are just the hypotenuse of a right triangle and since we have two pieces of metal
a² + b² = c² or L² + H² = Hyp² solving for the htpotenuse
Hyp = [tex]\sqrt[]{L^2 + H^2}[/tex]
so the total length of the gate metal is
P = 2( L + H) plus 2 Hyp = [tex]\sqrt[]{L^2 + H^2}[/tex]
= 2( 12 + 5) + 2 [ √(12² + 5²) ]
= 34 + 2 [ √( 144 + 25) ]
= 34 + 2 ( √169)
= 34 + 2( 13)
= 34 + 26
= 60 meters of gate metal metal weighs 2.5 kg per meter
Total weight equals 60 meters times 2.5 kg per meter
Total weight = 60 (2.5) = 150 kg
