Answer: 63.43 m
Explanation:
Given
Car lands 68.38 m away from the base of the garage
Stuntman drove the car with speed [tex]u=19\ m/s[/tex]
Since there is no acceleration in the horizontal direction, so there is no change in velocity
[tex]\Rightarrow 68.38=19\times t\\\Rightarrow t=3.598\ s[/tex]
time taken to cover 68.38 m is 3.598 s
In this time car travels a vertical distance of h
Such that we can write
[tex]\Rightarrow h=u_vt+\frac{1}{2}at^2\\\\\Rightarrow h=\frac{1}{2}gt^2\\\\\Rightarrow h=0.5\times 9.8\times (3.598)^2=63.43\ m[/tex]
