HELPWhat is the intensity of an electric field at a point where a 0.50 C
charge experiences a force of 20. N?
Remember to identity all of your data, write the equation, and show
your work. (5 points)

Respuesta :

Answer:intensity of an electric field (E)

charge (q)

Force (F)

E=F/q

E=20N/.5C

E=40N/C

Explanation:

The Electric field intensity will be  40 N/C

What is an Electric field intensity ?

The electric field intensity at a point is the force experienced by a unit positive charge placed at that point.

Electric field intensity(E) = force (F)/ charge(q)

given

charge = 0.50 C

Force = 20 N

Electric field intensity = ?

E = 20 N / 0.50 C

E = 40 N/C

The Electric field intensity will be  40 N/C

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