Explanation:
Drinking water requirement in town 2.0 m^3/s of water per second
nitrate in local well nitrate per 15 [tex]\mathrm{m}^{3}[/tex] of water
nitrate in distant reservoir [tex]=5 \mathrm{~g} / \mathrm{m}^{3}[/tex]
Let the flow rate of well
flow rate of reservoir [tex]=y m^{3} / s[/tex]
Drinking water requirement is [tex]45 \mathrm{ppm}[/tex] or [tex]45 \mathrm{~g} / \mathrm{m}^{3}[/tex]
therefore, the total flow of drinking water