Answer: 0.360 moles
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} FeCl_3=\frac{38.9g}{162.2g/mol}=0.240moles[/tex]
The balanced chemical reaction is:
[tex]2Fe+3Cl_2\rightarrow 2FeCl_3[/tex]
According to stoichiometry :
2 moles of require = 3 moles of
Thus 0.240 moles of [tex]FeCl_3[/tex] will require=[tex]\frac{3}{2}\times 0.240=0.360moles[/tex] of [tex]Cl_2[/tex]
Thus 0.360 moles of chlorine needed to react to produce 38.9 of iron (III) chloride.
