Respuesta :

Answer:

4.4pF

Explanation:

the capacitance of the circuit required for reception is given:

wL =  [tex]\frac{1}{wC}[/tex]

w = 2π [tex]f[/tex]

Using both equation

Capacitance is given

C =   1 - 4π2  f2 L

1- 4×9.8969×144×10 10 ×0.004

​=4.4pF