Answer: [tex]20\times 20, 16\times 25, 10\times 40[/tex]
Step-by-step explanation:
Given
The volume of the pool is [tex]1600\ ft^3[/tex]
Depth of water is [tex]d=4\ ft[/tex]
Suppose A is the base of the pool
[tex]\Rightarrow V=A\times d\\\Rightarrow 1600=A\times 4\\\Rightarrow A=400\ ft^2[/tex]
This area can be written as
[tex]\Rightarrow A=10\ ft\times 40\ ft\ or\\\Rightarrow A=16\ ft\times 25\ ft\ or\\\Rightarrow A=20\ ft\times 20\ ft[/tex]
