A simple random sample of 25 filtered 100 mm cigarettes isobtained, and the tar content of each cigarette is measured. The sample has a mean of 19.4 mg and a standard deviation of 3.23 mg. Use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg, which is the mean for unfiltered king size cigarettes.Please select all TRUE statements from those givem below.1. For this hypothesis test the P-value = .0072. There is sufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than21.1 mg.3. For this hypothesis test; H0; 1.1 H1: 21.14. For this hypothesis test the test statistic is t = -2.6325. service.php?service=cache&name=55e1f2083

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ogorwyne ogorwyne · Answer 1 · 2021-03-29T09:46:24+02:00

Answer:

h0:u ≥ 21.1

h1: u < 21.1

t statistics = -2.632

pvalu = 0.007

there is sufficient evidence to support claim

Step-by-step explanation:

null hypothesis

h0 = u≥21.1

alternative = u < 21.1

to get test statistics

barx - u / s/√n

= 19.4 - 21.1 / 3.23/√25

= -2.632

we calculate for the p value given this test statistics and the degree of freedom = 25-1 = 24

lest tailed p value = 0.0073 this is approximately 0.007

p value is less than the level of significance so we reject h0

we conclude that we have enough evidence to support h1, mean tar conent is less than 21.1