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Answer:

Step-by-step explanation:

5. angle FDE = 180-90-63 = 27°

 arc FE = 2×27 = 54°

6. arc GJ = 360-68-31-115 = 146°

 angle GHJ = 146/2 = 73°

7. angle GIJ = 146/2 = 73°

8. arc DAB = 2×101 = 202°

 arc BCD = 360°-202 = 158°

 angle A = 158/2 = 79°

 angle B = 360-79-110-68 = 112°

 

10. see picture

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5) The sum of angle in the triangle DEF is 180 degrees

mFE = <D

Recall that <D+<E+<F = 180⁰

<D+63+90 = 180

<D = 180-153

<D = 27 degrees

Hence the measure of arc FE is 27degrees

6) For this circle geometry, we will use the theorem

The sum of Opposite side of a cyclic quadrilateral is 180 degrees.

A + C = 180

m<A + 101 = 180

m<A = 180-101

m<A = 79degrees

Similarly

B + D = 180

m<B + 68 = 180

m<B = 180-68

m<B = 112degrees

7) The sum of angle in a circle is 360, hence;

arcGJ+68+31+115 = 36p

arcGJ = 360 - 214

arcGJ = 146⁰

Since the angle at the centre is twice angle at the circumference, then;

<GHJ = 1/2 arcGJ

<GHJ = 1/2(146)

<GHJ = 73⁰

<GHJ = <GIJ = 73⁰ (angle in the same segment of the circle are equal)

8) Recall that the sum of Opposite side of a cyclic quadrilateral is 180 degrees.

P + R = 180

57 + <R = 180

m<R = 180-57

m<R = 123degrees

Similarly, m<Q+m<S = 180⁰

Since the triangle in a semi circle is a right angled triangle, hence m<Q = 90 degrees (triangle PQR is a right angled triangle)

m<S = 180 - 90

m<S = 90 degrees

Learn more here: brainly.com/questions/11325504