By definition, we have to:
[tex] vf = a * t + vo
[/tex]
Where,
vf: final speed
vo: initial speed
t: time
a: acceleration
Clearing the acceleration we have:
[tex] a = \frac{vf-vo}{t}
[/tex]
When replacing values we have to take into account two things:
1) Assume that the given speeds are positive
2) The time must be in seconds
The time in seconds is:
[tex] t = 33 * 60
t = 1980
[/tex]
Then, replacing values we have:
[tex] a =\frac{7.1-2.7}{1980}
[/tex]
[tex] a = 0.002 \frac{m}{s ^ 2}
[/tex]
Answer:
The average acceleration of the treadmill during this period is:
[tex] a = 0.002 \frac{m}{s ^ 2}
[/tex]
