Can someone please help me how to set this up?

A police car receives a radio call to catch a vehicle which is speeding down the highway at 80 mph. The police car, which is 12 miles away, drives after it at 108 mph. How long will it take for the police car to catch up? ...?

Respuesta :

The car has a 12 mile head start, going 80 mph, so his distance is:dcar=80∗t+12
The is going at 108 mph, so his distance is:dcop=108t
Setting them equal to each other we get:80t+12=108t⇒12=28t⇒t=1228=37
So 3/7 of an hour.about 25.7 mins.

Answer:

The time is 0.428 hr.

Explanation:

Given that,

Final speed = 108 mph

Initial speed = 80 mph

Distance = 12 miles

We need to calculate the time

Using formula of time

[tex]v = \dfrac{d}{t}[/tex]

d = distance

t = time

Put the value into the formula

[tex]108-80=\dfrac{12}{t}[/tex]

[tex]t = \dfrac{12}{108-80}[/tex]

[tex]t =0.428\ hr[/tex]

Hence, The time is 0.428 hr.