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antonsandiego
To find the discriminant of the following equation you have to remember tha main formula :  ax^2 +bx + c and the one for discriminant is  b^2 -4ac
So, now we can solve it [tex]16^2 -4(16)(4) = 4^2-4(4)[/tex]
[tex](4^2)^2 -4(4)(4)(4)-4^2 +4(4) = 0[/tex]
[tex]4^4 - 4^4 = 0[/tex][tex]16^2-4*4*16=0[/tex] , so the discriminants is 0 :) 
Hope it's clear!

Answer:

The discriminant is 0.

Step-by-step explanation:

Since, the discriminant of a quadratic equation [tex]ax^2+bx+c=0[/tex] is,

[tex]D=b^2-4ac[/tex]

Here, the given equation is,

[tex]4x^2+16x+16=0[/tex]

By comparing,

a = 4, b = 16 and c = 16,

Hence, the discriminant of the given equation is,

[tex]16^2-4\times 4\times 16[/tex]

[tex]=256 - 256[/tex]

[tex]=0[/tex]

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