You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.

Let x be the number of bratwursts and y the number of hamburgers. whiichs system of inequalities represents this situation?

Options:
x+y<=40 1.35x+1.2y>=175
x+y<=40 1.35x+1.2y<=175
x+y>=120 1.35x+1.2>=175
x+y>=120 1.35x+1.2<=175
...?

Respuesta :

x+y>=120 1.35x+1.2<=175

Is the logical interpretation of this scenario.

Answer:

Option D -[tex]x+y\geq 120[/tex] , [tex]1.35x + 1.2y \leq 175[/tex]

Step-by-step explanation:

Given : You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.

To find : Which system of inequalities represents this situation?

Solution :

Let x be the number of bratwursts and y the number of hamburgers.

You want at least three bratwursts or hamburgers for each of your 40 guests.

i.e, you want at least [tex]3\times(40)=120[/tex]  bratwursts or hamburgers.  

We can write the equation as,

Number of bratwursts + number of hamburgers at least 120

[tex]x+y\geq 120[/tex]

Bratwursts cost $1.35 each and hamburgers cost $1.2 each. Your budget is $175.

We can write equations as ,

Cost of bratwursts + cost of hamburgers at most 175

[tex]1.35x + 1.2y \leq 175[/tex]

Therefore, The system of linear equation form is [tex]x+y\geq 120[/tex], [tex]1.35x + 1.2y \leq 175[/tex]

Hence, Option D is correct.