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Express answer in exact form.

A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.

(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4 s2 √3.)

Respuesta :

A - area of a segment formed by a side of the hexagon and the circle
A = {area of a sector of a circle} - {area of an equilateral triangle}

[tex]A= \frac{r^2\pi\alpha}{360^o} - \frac{r^2\sqrt{3}}{4}= \frac{3^2\pi 60^o}{360^o} - \frac{3^2\sqrt{3}}{4}=\frac{9\pi }{6} - \frac{9\sqrt{3}}{4}= \frac{9}{2} (\frac{\pi }{3} - \frac{\sqrt{3}}{2})[/tex]
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th3l3g3ndz21

Answer:

A = { 3/2 π - 9/4 √ 3 } in^2

Step-by-step explanation:

Hope it helps, sorry for answering late.

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