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Please help me solve this word problem:
In a round-robin chess tournament, each player is paired with every other player once. The function shown below, models the number of chess games, "N", that must be played in a round-robin tournament with "t" chess players. In a round-robin chess tournament, 55 games were played. How many players entered the tournament?

N=t^2-t divided by 2.

Respuesta :

syed514
solve 55=(t^2−t)/2 for t
t2−t=110
t2−t−110=0
(t−11)(t+10)=0


t=11
aramisdegaula1977

Answer:

t = 11

Step-by-step explanation:

From the equation that gives, the number of games you can get the number t of players who participated in the ronund-robin tormeo, is:

[tex]N = \frac{t ^ 2-t}{2}[/tex]

[tex]55 = \frac{t ^ 2-t}{2}[/tex]

[tex]110 = t ^ 2-t[/tex]

[tex]t ^ 2-t -110 = 0[/tex]

[tex](t-11) (t + 10) = 0[/tex].  Then

[tex]t - 11 = 0\\t = 11\\t + 10 = 0\\t = -10[/tex]

Since t cannot take negative values, then t = 11.

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