Answer:
[tex]1+\sqrt{2}[/tex]
Step-by-step explanation:
We have been given a radical expression [tex]\sqrt{3+2\sqrt{2}}[/tex]. We are asked to simplify the given expression.
We will add [tex](\sqrt{2})^2-2[/tex] to our given expression as after adding and subtracting same quantity the value of our expression will be same.
[tex]\sqrt{3+2\sqrt{2}+(\sqrt{2})^2-2}[/tex]
[tex]\sqrt{3-2+2\sqrt{2}+(\sqrt{2})^2}[/tex]
[tex]\sqrt{1+2\sqrt{2}+(\sqrt{2})^2}[/tex]
Using perfect square formula [tex](a+b)^2=a^2+2ab+b^2[/tex] we can rewrite our expression as:
[tex]\sqrt{1^2+2\sqrt{2}\cdot 1+(\sqrt{2})^2}[/tex]
[tex]\sqrt{(1+\sqrt{2})^2}[/tex]
Applying radical rule [tex]\sqrt[n]{x^n} =x[/tex], we will get,
[tex](1+\sqrt{2})^{\frac{2}{2}}=1+\sqrt{2}[/tex]
Therefore, the simplified form of our given expression would be [tex]1+\sqrt{2}[/tex].
