Respuesta :
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
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Answer:
If the velocity of a car is halved, the centripetal force required to keep it in path of constant radius becomes one fourth of the initial force.
Explanation:
The centripetal force is required to move an object in circular path. Mathematically, the formula of the centripetal force is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
Here,
m is the mass of the object
v is the velocity of object
r is the radius of the circular path
If the velocity of the car is halved, v'=v/2
New centripetal force is given by :
[tex]F'=\dfrac{mv'^2}{r}[/tex]
[tex]F'=\dfrac{1}{4}\times \dfrac{mv^2}{r}\\\\F'=\dfrac{1}{4}\times F[/tex]
New centripetal force becomes one fourth of the initial force, when the velocity of a car is halved.
