Respuesta :
I have my solution here with a different question:
What is the probability that the number on the red die is smaller than the number on the white die?
5/12
There are 36 possible ways of throwing a dice twice. If the first throw is 1, then there are five possibilities for a greater throw in the second; if the first throw is 2, then there are four, and so on.
Thus the total number where the second throw is greater than the first is 5 + 4 + 3 + 2 + 1 + 0 = 15, so the probability is 15 / 36 = 5 / 12
There is a 5/6 chance that the dice are different.
There is a 1/2 chance that the first will be bigger for two different dice.
The probability is 5/6 x 1/2 = 5/12
I hope the method and technique in my solution might help you solve your problem.
What is the probability that the number on the red die is smaller than the number on the white die?
5/12
There are 36 possible ways of throwing a dice twice. If the first throw is 1, then there are five possibilities for a greater throw in the second; if the first throw is 2, then there are four, and so on.
Thus the total number where the second throw is greater than the first is 5 + 4 + 3 + 2 + 1 + 0 = 15, so the probability is 15 / 36 = 5 / 12
There is a 5/6 chance that the dice are different.
There is a 1/2 chance that the first will be bigger for two different dice.
The probability is 5/6 x 1/2 = 5/12
I hope the method and technique in my solution might help you solve your problem.
