This is a right triangle problem. c^2 = a^2 + b^2
Let b = 7 mi (Rosa's distance from home)
Let a = the east leg (Juan's distance from home
(a+1) = c (hypotenuse, distance between them)
(a+1)^2 = a^2 + 7^2
FOIL (a+1)(a+1)
a^2 + 2a + 1 = a^2 + 49
Combine like terms
a^2 - a^2 + 2a = 49 - 1
2a = 48
a =
a = 24 mi, Juan's distance from home
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