Respuesta :
Answer:[tex]510. 12 cm^3[/tex]
The volume of a cylindrical conduit, [tex]V=\pi (r_2^2-r_1^2) h[/tex]
where [tex]r_1[/tex] is the inner radius, [tex]r_2[/tex] is the outer radius, h is the length.
First of all, we would covert each parameter into centimeters.
length of the conduit, [tex] h=4 ft=4\times 30.48 cm=121.92 cm[/tex]
outer radius, [tex]r_1=2.2/2 in =1.1 in= 1.1\times 2.54 cm=2.79 cm[/tex]
inner radius, [tex]r_1=2/2 in =1 in= 2.54 cm[/tex]
Insert the values in the volume formula,
[tex]V=3.14 \times (2.79^2-2.54^2) \times 121.92 cm^3=510. 12 cm^3[/tex]
Hence, the volume of metal in the conduit is 510. 12 cubic centimeters.
