If you were to use the substitution method to solve the following system, we need to write one of the equation to an expression equivalent to y. Let us say the second equation, we write it as follows:
6x – 3y = –3
-3y = -6x - 3
y = 2x + 1
We substitute the equation to the first given equation as follows:
2x – 5y = –3
2x – 5(2x + 1) = –3
2x - 10x - 5 = -3
-8x = 2
x = -1/4
y = 2(-1/4) + 1 = 1/2
