Respuesta :
The solution to the problem is as follows:
Li=Iw
Li=1/2 MR^2 * w
w = 2pi*angular frequency
Li=1/2 MR^2 * (2pi*angular frequency)
Substituting:
Li = 1/2*5.7kg*0.43m^2*2*pi*20rev/s
Li = 66.22
Therefore, the magnitude of the angular momentum is 66.22.
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Li=Iw
Li=1/2 MR^2 * w
w = 2pi*angular frequency
Li=1/2 MR^2 * (2pi*angular frequency)
Substituting:
Li = 1/2*5.7kg*0.43m^2*2*pi*20rev/s
Li = 66.22
Therefore, the magnitude of the angular momentum is 66.22.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer : [tex]L=66.18\ kgm^2/s[/tex]
Explanation :
It is given that,
Mass, m = 5.7 kg
radius, R = 0.43 m
frequency, f = 20 rev/s
Angular momentum, [tex]L=I\omega[/tex]
I is the moment of inertia of disk, [tex]I=\dfrac{MR^2}{2}[/tex]
we know that, [tex]\omega = 2\pi \nu[/tex]
so, [tex]L=MR^2\pi \nu[/tex]
[tex]L= 5.7\ kg\times (0.43\ m)^2\times3.14\times 20\ rev/s[/tex]
[tex]L=66.18\ kgm^2/s[/tex]
Hence, the magnitude of angular momentum of spinning disk is [tex]66.18\ kgm^2/s[/tex].
