Can someone please help me with this...
A stone is dropped from the edge of a roof, and hits the ground with a velocity of −185 feet per second. Assume the acceleration due to gravity is -32 feet per second squared. How high (in feet) is the roof? ...?
The way I solve this problem is through a series of two equations. The equations are
Vf = Vo + gt (1)
and
x = Vo*t + 0.5*g*t^2 (2)
where Vf is the final velocity Vo is the initial velocity (equal to zero) g is the acceleration due to gravity t is the time of travel x is the distance traveled.
The first eqn is used to calculate the time it takes to reach the bottom. Therefore, substituting value to eqn 1, we get
185 = 32*t t = 5.78 s
The second equation can be used to calculate the height of the roof
