Work is equal to a force over a distance and is equal to the change in kinetic energy, so
- Fd=ΔKE
−Fd=1/2mv22−1/2mv21
d=(1/2mv22−1/2mv21)/−F
We know that Ffric=kFnatural and Fnatural=mg so:
d=(1/2mv22−1/2mv21)/−(k∗mg)d=(−1/2v21)/−(k∗g)
d=(−1/2×(14.6m/s)2)/−(0.137×9.8m/s)
d = 78.9m
