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  • 23-11-2016
  • Mathematics
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What are the discontinues of the function f(x) = x^2 - 16/6x-24

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nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 24-11-2016
The function f(x) = (x^2 - 16) / (6x - 24) is discontinuos at
6x - 24 = 0
6x = 24
x = 4.
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