Respuesta :

6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)=  0.67

Answer : The answer is, [tex]0.67\text{ Kg}/mole\text{ dL}[/tex]

Step by step explanation :

For this problem the conversion factors used are,

[tex](1kg=1000g)\\\\(1L=10dL)[/tex]

Convert [tex]6.7\times 10^3\text{ g}/mole\text{ L}[/tex] to [tex]\text{ Kg}/mole\text{ dL}[/tex] :

[tex]6.7\times 10^3\text{ g}/mole\text{ L}\\\\\Rightarrow \frac{6.7\times 10^3}{10^3}\text{ Kg}/mole\text{ L}\\\\\Rightarrow \frac{6.7}{10}\text{ Kg}/mole\text{ dL}\\\\\Rightarrow 0.67\text{ Kg}/mole\text{ dL}[/tex]

Hence, the answer is, [tex]0.67\text{ Kg}/mole\text{ dL}[/tex]