Change in velocity ([tex]\Delta v[/tex]) is acceleration ([tex]a[/tex]) times time ([tex]t[/tex])
Acceleration [tex]a=1.2\ m/s^{2}[/tex]
Time [tex]t=10\ s[/tex]
So [tex]\Delta v=at=1.2\ m/s^{2}*10\ s=12\ m/s[/tex]
The initial velocity is then [tex]16\ m/s-12\ m/s=4\ m/s[/tex]
