hsmo
hsmo
24-11-2016
Mathematics
contestada
Solve the exponential equation algebraically
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garcialnatalia
garcialnatalia
24-11-2016
2^x=33
log2^x=log33
xlog2=log33
(xlog2)/log2 = (log33)/log2
x=(log33)/log2= 5.04439411936
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apologiabiology
apologiabiology
24-11-2016
hmm, ok
so rememeber
[tex]log_ab=c[/tex] means [tex]a^c=b[/tex]
therefor
[tex]a^c=b[/tex] is to [tex]2^x=33[/tex]
as is
[tex]log_ab=c[/tex] is to [tex]log_233=x[/tex]
x=[tex]log_233[/tex] or aprox 5.04439
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