cr3dianlam0pso cr3dianlam0pso
  • 24-11-2016
  • Mathematics
contestada

Find the axis of symmetry of the graph of the function.

f(x) = 2x2 - 16x + 27

A. x = -3

B. x = 4

C. x = -5

D. x = 6

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apologiabiology
apologiabiology apologiabiology
  • 24-11-2016
for f(x)=ax^2+bx+c
the axis of symmetry is -b/2a

f(x)=2x^2-16x+27
a=2
b=-16
-b/2a=-(-16)/2(2)=16/4=4
x=4

B is answer

Answer Link
syed514
syed514 syed514
  • 27-11-2016
x will be equal to 4. So, the right answer is B.
Answer Link

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