Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2.

answers:
The zeros are approximately 0.2, 0.7, and 2.7.
The zeros are approximately –2.7, –1.7, and 0.2.
The zeros are approximately –0.2, –0.7, and 2.7.
The zeros are approximately –0.5, –0.7, and 1.7.

Correct answer is C.

[tex]-5 x^3 + 9 x^2 +12 x+ 2=(-5 x-1) \left(x^2-2 x-2\right) \\ \\\left\{-\frac{1}{5},1-\sqrt{3},1+\sqrt{3}\right\}\to \{-0.2,-0.732051,2.73205\}[/tex]

Or check if f(0.2) = 0 to eliminate A and B.
Then check if f(-0.5) = 0 to eliminate D.

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anbundy anbundy · Answer 2 · 2020-05-25T21:01:18+02:00

anbundy anbundy

25-05-2020

Answer:

the answer is C

Step-by-step explanation:

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Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2. answers: The zeros are approximately 0.2, 0.7, and 2.7. The zeros are approximately –2.7, –1.7, and 0.2. The zeros are approximately –0.2, –0.7, and 2.7. The zeros are approximately –0.5, –0.7, and 1.7.

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Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2.

answers:
The zeros are approximately 0.2, 0.7, and 2.7.
The zeros are approximately –2.7, –1.7, and 0.2.
The zeros are approximately –0.2, –0.7, and 2.7.
The zeros are approximately –0.5, –0.7, and 1.7.