an815
Helping Hand
line through point (a,b) with slope is given by y-b=m(x-a) slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore. y-3=-9/4*(x-4) y-3=-9/4x+9 y=-9/4x+9+3 y=-9/4x+12
Line y = 4/9 x - 2 has a slope of 4/9. For perpendicular lines, the ploduct of the two slopes is -1. Thus the slope of the required line is -1/(4/9) = -9/4
Equation of a line is given by y - y1 = m(x - x1) y - 3 = -9/4(x - 4) y - 3 = -9/4 x + 9 y = -9/4 x + 9 + 3 y = -9/4 x + 12.
