A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

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Answer:

The total possible outcomes that exist are:

                             2400

Step-by-step explanation:

We are given four dices:

first is a standard 6-faced die.

The second die has 4 faces.

Third dice has 10 faces.

Fourth dice has 10 faces.

Now when all the dice are thrown together then the total number of possible outcomes are:

   [tex]4\times 6\times 10\times 10=2400[/tex]

( Since there are 4 numbers possible for the first die, 6 for second and 10 each for third and fourth)

                    The answer is:

                           2400

Answer:

2400

Step-by-step explanation: i got it right