Respuesta :
Give that the area of the circle, A is directly proportional to the square of its radius, R.
AαR2
A=kR2
, where k is some constant. WHen your radius is halved, R/2. SUbstitute R/2 into the original R,
k(R2)2
=k(R24)
=14kR2
Since A = k R^2, Substituting into the above equation, we will get 1/4 A.
Area of the circle decreases by a factor of 1/4Give that the area of the circle, A is directly proportional to the square of its radius, R. AαR2A=kR2where k is some constant. When your radius is halved, R/2. Substitute R/2 into the original R, k(R2)2 =k(R24) =14kR2 Since A = k R^2, Substituting into the above equation, we will get 1/4 A. Area of the circle decreases by a factor of 1/4
AαR2
A=kR2
, where k is some constant. WHen your radius is halved, R/2. SUbstitute R/2 into the original R,
k(R2)2
=k(R24)
=14kR2
Since A = k R^2, Substituting into the above equation, we will get 1/4 A.
Area of the circle decreases by a factor of 1/4Give that the area of the circle, A is directly proportional to the square of its radius, R. AαR2A=kR2where k is some constant. When your radius is halved, R/2. Substitute R/2 into the original R, k(R2)2 =k(R24) =14kR2 Since A = k R^2, Substituting into the above equation, we will get 1/4 A. Area of the circle decreases by a factor of 1/4
