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The sides of triangle ABC are 4.5feet 7.5 ft and 9 ft.The area is about 17 square feet. Explain how to use the are of triangle ABC to find the area of a triangle DEF with side lengths of 6 ft 10 ft and 12ft.Thank you

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metchelle
In order to get the area of a triangle using sides, the formula that we are going to use is Heron's formula. This is after from "Hero of Alexandria".
So here is the step by step process:
First, we calculate for s (half of the triangles perimeter) s = a+b+c divided by 2.
s = 6 + 10 + 12 / 2
s =28/2
s = 14
Now that we have the s, we can now calculate for the area.
A = square root of s(s-a)(s-b)(s-c)
A= square root of 14 x 8 x 4 x 2
A= square root of 896
A = 29.93
The area of triangle DEF is 29.93 square feet or 30 square feet. Hope this answer helps. 
Blacklash

Answer:

Area of DEF = 30.22 square feet

Step-by-step explanation:

Let us find the ratio of sides of the triangles

    [tex]\frac{6}{4.5}=\frac{4}{3}[/tex]

    [tex]\frac{10}{7.5}=\frac{4}{3}[/tex]    

    [tex]\frac{12}{9}=\frac{4}{3}[/tex]

So DEF is a similar triangle to ABC with proportion [tex]\frac{4}{3}[/tex]

If the sides are in a proportion m their areas are in proportion m²

 Area of DEF [tex]=\left ( \frac{4}{3} \right )^2\times[/tex] Area of ABC

Area of DEF [tex]=\left ( \frac{4}{3} \right )^2\times 17[/tex]

Area of DEF = 30.22ft²

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