Respuesta :
Assuming Earth's gravity, the formula for the flight of the particle is:
s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160.
This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2.
Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet.
s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160.
This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2.
Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet.
Answer : [tex]H = 484 feet[/tex]
Explanation :
Given that,
Initial height = 160 feet
Initial speed = 144 feet/ sec
Using third equation of motion
[tex]v^{2} = u^{2} + 2gh[/tex]
[tex]0 = (144)^{2}\ feet/s+2\times -32feet/s^{2}\times h[/tex]
[tex]h = 324 feet[/tex]
Now the maximum height
H = h + initial height
[tex]H = 324 feet + 160 feet[/tex]
[tex]H = 484 feet[/tex]
Hence, this is the required solution.
