Respuesta :
y > = 2 | x - 1| - 2...subbing in (1,0)
0 > = 2 | 1 - 1| - 2
0 > = 2 (0) - 2
0 > = -2...correct....so (1,0) is part of the solution
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y > | x + 1| - 1...subbing in (1,1)
1 > | 1 + 1| - 1
1 > 2 - 1
1 > 1....incorrect....so (1,1) is not part of the solution
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less then or equal....dashed line, shaded below
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x = cashier job hrs, y = babysitting hrs
y > = 0
x > = 0
6x + 6y = 60
x < = 12
y < = 12
0 > = 2 | 1 - 1| - 2
0 > = 2 (0) - 2
0 > = -2...correct....so (1,0) is part of the solution
=====================
y > | x + 1| - 1...subbing in (1,1)
1 > | 1 + 1| - 1
1 > 2 - 1
1 > 1....incorrect....so (1,1) is not part of the solution
=====================
less then or equal....dashed line, shaded below
=====================
x = cashier job hrs, y = babysitting hrs
y > = 0
x > = 0
6x + 6y = 60
x < = 12
y < = 12
Answer:
Part 1) The points 1,2 and 4 are part of the solution
Part 2) The point 2 is not part of the solution
Part 3) Option 2. Dashed line, shade below
Part 4) The system of inequalities is
[tex]y\geq-x+10[/tex]
[tex]y\leq -x+12[/tex]
Step-by-step explanation:
Part 1) we have
[tex]y\ge\left|x-1\right|-2[/tex]
Using a graphing tool
The graph in the attached figure
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must be belong to the shaded area of the solution
Plot the points
The points , 1,2 and 4 belong to the shaded area
therefore
The points 1,2 and 4 are part of the solution
Part 2) we have
[tex]y>\left|x+1\right|-1[/tex]
Using a graphing tool
The graph in the attached figure
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must be belong to the shaded area of the solution
Plot the points
The point 2 not belong to the shaded area
therefore
The point 2 is not part of the solution
Part 3) we have
[tex]y>5x-1[/tex] -----> first inequality
[tex]y\leq-x[/tex] -----> second inequality
we know that
The solution of the second inequality is the shaded area below to the dashed line
The equation of the dashed line is [tex]y=-x[/tex]
Part 4)
Let
x------> the number of hours at work as a cashier
y------> the number of hours at work as a baby sit
we know that
[tex]6x+6y\geq 60[/tex]
Simplify
[tex]x+y\geq 10[/tex]
[tex]y\geq-x+10[/tex] -----> inequality A
[tex]x+y\leq 12[/tex]
[tex]y\leq -x+12[/tex] ----> inequality B
[tex]x\geq 0[/tex] -----> inequality C
[tex]y\geq 0[/tex] -----> inequality D
The solution is the shaded area
see the attached figure


