Answer: 15 L of [tex]N_2[/tex] gas will have same numer of molecules as 15L of [tex]CO_2[/tex] gas at the same temperature and pressure,
Explanation:
According to avogadro's law, equal moles of gases occupy equal volume at same conditions of temperature and pressure.
[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}[/tex]
[tex]\text{Number of moles of} CO_2=\frac{15L}{22.4L/mol}=0.67mol[/tex]
[tex]1 mole of CO_2[/tex] contains=[tex]6.022\times 10^{23}[/tex] molecules of [tex]CO_2[/tex]
Thus 0.67 moles of [tex]CO_2[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 0.67=4.03\times 10^{23}[/tex] molecules
Now molecules of [tex]N_2[/tex] = molecules of [tex]CO_2[/tex] = [tex]4.03\times 10^{23}[/tex]
[tex]6.023\times 10^{23}[/tex] molecules of [tex]N_2[/tex] = 22.4 L
Now [tex]4.03\times 10^{23}[/tex] molecules of [tex]N_2[/tex] = [tex]\frac{22.4}{6.023\times 10^{23}}\times 4.03\times 10^{23}=15L[/tex]