Answer:
Step-by-step explanation:
From the diagram,
i. To prove that; ΔBAD ≅ ΔABC
It can be inferred that;
<BAD ≅ <ABC (right angle of a triangle)
AC ≅ BD (diagonal of a rectangle)
AD ≅ BC (property of the sides of a rectangle)
AB ≅ CD (property of the sides of a rectangle)
Therefore,
ΔBAD ≅ ΔABC (SAS, Side-Angle-Side, congruent relations)
ii. From the given rectangle,
AC = BD = diagonal
Since;
AD ≅ BC (property of the sides of a rectangle)
AB ≅ CD (property of the sides of a rectangle)
Then,
AC ≅ BD (diagonal property of a rectangle)
