Use the scenario to answer the following question.

A group of students working in a chemistry lab is planning a procedure to neutralize 25.0mL of 2.0 M hydrochloric acid (strong acid) with 1.0 M potassium hydroxide (strong base). In their procedure they plan on adding an equal volume of the base to the acid.

What would be the expected outcome of carrying out this step as planned?

A.
The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.

B.
The resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

C.
The resulting pH will be greater than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

D.
The resulting pH will not be able to be determined because the concentrations of the acid and base are not the same.

B. The resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

You have 2.0 M HCl and 1.0 M KOH. If you have 25 mL of both, you have double the moles of HCl, since it’s more concentrated, so your final solution will still be acidic.

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Sam1s Sam1s · Answer 2 · 2022-03-23T18:37:51+01:00

The expected outcome of carrying out this step as planned is :

B. The resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

Acid and bases

The expected outcome of carrying out this step as planned is the resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.

pH may be a degree of how acidic/basic water is.

The run goes from - 14, with 7 being unbiased. pHs of less than 7 demonstrate causticity, while a pH of more noteworthy than 7 demonstrates a base.

pH is truly a degree of the relative amount of free hydrogen and hydroxyl particles within the water

Thus, the correct answer is B.

Learn more about "Acids":

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