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A spider walks on the outside of a rectangular prism box from point A to B to C to D, then strings a web from point D to point E. What is the total distance of the spider’s path, rounded to the nearest tenth of an inch?

A spider walks on the outside of a rectangular prism box from point A to B to C to D then strings a web from point D to point E What is the total distance of th class=

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mhanifa

Answer:

  • 76 in

Step-by-step explanation:

Use Pythagorean to solve diagonals.

Find the measure of each segment and add together:

  • AB = [tex]\sqrt{AE^2 + EB^2}[/tex] = [tex]\sqrt{(18 - 9)^2+12^2}[/tex] = [tex]\sqrt{225}[/tex] = 15 in
  • BC = [tex]\sqrt{CE^2+BE^2}[/tex] =  [tex]\sqrt{18^2 + 12^2}[/tex] = [tex]\sqrt{468}[/tex] = 21.6 in
  • CD =  [tex]\sqrt{10^2+12^2}[/tex] = [tex]\sqrt{244}[/tex] = 15.6 in
  • DE = [tex]\sqrt{10^2 + 12^2 + 18^2}[/tex] = [tex]\sqrt{568}[/tex] = 23.8 in

Total distance:

  • 15 + 21.6 + 15.6 + 23.8 = 76 in

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