Respuesta :

Hello, the answer would be -118*C

A 1.26 g sample of He gas has a pressure of 0.123 arm and a volume of 32.6 L, then the temperature of the gas is -117.7 degree C.

How do we calculate the temperature of gas?

Temperature of any gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = 0.123 atm

V = volume of gas = 32.6 L

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature of gas = ?

n is moles of He gas and will be calculated as:

n = W/M, where

W = given mass = 1.26g

M = molar mass = 4 g/mol

n = 1.26 / 4 = 0.315 moles

On putting values we get,

T = (0.123)(32.6) / (0.315)(0.082)

T = 155.41 K = 155.41 - 273.15 = -117.7 degree C

Hence required temperature of the helium sample is -117.7 degree C.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/25290815