4.2


The solid was created by connecting two congruent square pyramids to a rectangular prism.


18 in


x


15


1


15 in.


What is the surface area of this solid?


square inches

Respuesta :

Answer:

The answer is "[tex]\bold{1920 \ in^2}[/tex]".

Step-by-step explanation:

Please find the graph file.

Rectangular solid area:

Its region comprises four rectangles, each 15 for each case 14 in each.

The rectangle field is the formula [tex]A = lw[/tex]

The four rectangles are therefore covered by a zone: [tex]\to A = 4lw = 4 \times 15 \ in \times 14 \ in = 840 \ in^2.[/tex]

square Pyramids area:

The pyramids in both squares have 8 triangular facets.

Each triangle has a 15-inch basis with a 14-inch base.

The triangle zone formulation is [tex]A = \frac{1}{2}bh[/tex]

That's it. The 8 triangles area is [tex]\to A = 8 \times \frac{1}{2}bh = 4bh = 4 \times 15 \ in \times 18 \ in = 1080 \ in^2[/tex]

Total field surface:

Strong rectangular[tex]= 840 \ in^2[/tex]

Pyramids in the Square[tex]= 1080[/tex]

Overall area [tex]= 1920 \ in^2[/tex]

The number is [tex]1920\ in^2[/tex] for a total area.

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