Given:-
- Points C = (-7,2) → [tex]\sf{(X_1,Y_1)}[/tex]
- D = (3,12) → [tex]\sf{(X_2,Y_2)}[/tex]
To Find:-
Required Response:-
Let,
Midpoint of CD be (x,y).
WKT,
[tex]\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}[/tex]
[tex]→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}[/tex]
[tex]→\;{\sf{\frac{-4}{2},\frac{14}{2}}}[/tex]
[tex]→\;{\sf{-2,7}}[/tex]
The Midpoint of CD ◕➜ [tex]\Large{\red{\mathfrak{(-2,7)}}}[/tex]
Let,
The centre be O
Radius = CO & OD
Here, C = (-7,2) → [tex]\sf{(X_1,Y_1)}[/tex]
O = (-2,7) → [tex]\sf{(X_2,Y_2)}[/tex]
[tex]\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}[/tex]
[tex]→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}[/tex]
[tex]→\;{\sf{\sqrt{5²+5²}}}[/tex]
[tex]→\;{\sf{\sqrt{25+25}}}[/tex]
[tex]→\;{\sf{\sqrt{50}}}[/tex]
[tex]→\;{\sf{5√2 (or) 7.07}}[/tex]
Radius of Circle ◕➜ [tex]\Large{\red{\mathfrak{7.07}}}[/tex]
Option D.
Hope It Helps You ✌️
